Question 1106663
the equations to solve are:


−2x − 3y = −13


x + y = 6 


in the second equation, solve for x to get x = -y + 6.


in the first equation, replace x with (-y + 6) to get -2(-y+6) -3y = -13.


simplify to get 2y - 12 - 3y = -13


combine like terms to get -y - 12 = -13


solve for y to get y = 1.


go back to your original equations.


they are:


−2x − 3y = −13


x + y = 6 



replace y in the second equation with 1 to get x + 1 = 6


solve for x to get x = 5.


your solution is x = 5 and y = 1.


replace x with 5 and y with 1 in the first original equation to get −2(5) − 3(1) = −13


simplify to get -10 - 3 = -13 which reduces to -13 = -13 which is true.


this conforms the solution is correct.


your solution is (x,y) = (5,1).


your choices are:


1) −y+6, (5,1) 
2) y+6, (-1/5 ,1/5) that's meaning 1 over neg 5,and 1 over 5

3)-3/2y+13/2 (5,1) 
4) 6−y, (1,5) 


eliminate selection 2 and 4 because their coordinate solution is not (5,1).


that leaves selection 1 or selection 3.


you were asked to substitute for x in the first equation.


you did that by solving for x in the second equation and then substituting for x in the first equation.


when you solved for x in the second equation, you got x = -y + 6.


you solution is therefore selection 1.


selection 1 is:


1) −y+6, (5,1) 


the first part of that selection is the value that you substituted for x.


the second part of that selection is the solution in coordinate form.