Question 1106605
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<pre>
Let x be the cost of the first bike for the man, 

and y be the cost of the second bike for the man.


From the condition we know that 

1.15x = 35000  and  1.2y = 35000.


Then  x = {{{35000/1.15}}} = 30434.78 dollars  and  y = {{{35000/1.2}}} = 29166.37.


Thus his overal percentage of profit  is  {{{((2*35000)/(30434.78 + 29166.37)-1)*100}}} = 0.1745 = 17.45%.
</pre>

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On percentage problems, see the lessons  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/percentage/lessons/Percentage-problems.lesson>Percentage problems</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Percentage-and-ratio-word-problems/Percentage-word-problems-%28Type-1-problems-Finding-the-Part%29.lesson>Percentage word problems (Type 1 problems, Finding the Part)</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Percentage-and-ratio-word-problems/Percentage-word-problems-%28Type-2-problems-Finding-the-Rate%29.lesson>Percentage word problems (Type 2 problems, Finding the Rate)</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Percentage-and-ratio-word-problems/Percentage-word-problems-%28Type-3-problems-Finding-the-Base%29.lesson>Percentage word problems (Type 3 problems, Finding the Base)</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Percentage-and-ratio-word-problems/More-complicated-percentage-problems.lesson>More complicated percentage problems</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/Percentage-and-ratio-word-problems/Problems-on-percentage-that-lead-to-unexpected-results.lesson>Problems on percentage that lead to unexpected results</A>

in this site.