Question 1106521
let x = the hourly wage of the manager.
let y = the hourly wage of the clerk.


your equations are:


x = 2y - 1.75


x - y = 6.75


these are two equations that need to be solved simultaneously.


there are several ways to solve them.


this is only one of them.


your two equations are:


x = 2y - 1.75


x - y = 6.75


in the second equation, solve for x to get x = y + 6.75


your two equations are now:


x = 2y - 1.75


x = y + 6.75


subtract the second equation from the first to get:


0 = y - 8.50


solve for y to get y = 8.50


from the equation of x = y + 6.75, replace y with 8.50 to get x = 8.50 + 6.75.


this makes x equal to 15.25


you have:


x = 15.25
y = 8.50


x = 2y - 1.75 becomes x = 17 - 1.75 which becomes x = 15.25.


x - y becomes 15.25 - 6.75 = 8.50.


all the requirements of the problem are confirmed to be true, so the solution can assumed to be good.


the solution is that the the hourly wage for the managers is 15.25 per hour.