Question 1106524
{{{tan^""(2theta)}}}{{{""=""}}}{{{(2tan^""(theta))/(1-tan^2(theta))}}}{{{""=""}}}{{{(2(1/4))/(1-(1/4)^2)}}}{{{""=""}}}{{{(1/2)/(1-1/16)}}}{{{""=""}}}{{{(1/2)/(15/16)}}}{{{""=""}}}{{{(1/2)*(16/15)}}}{{{""=""}}}{{{""=""}}}{{{8/15}}}