Question 1106377
{{{y=-(2/3)x+3}}}


{{{let}}}{{{y=0}}}.

{{{-2x/3+3=0}}}

{{{-2x/3=-3}}}

{{{x=3*(3/2)}}}

{{{x=9/2=4&1/2}}}



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Use the gradient to and the y-coordinate on the line where: i) x=6 ii) x=9
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You could make the graph and read the points from the graph or you can use algebra or arithmetic.  If you choose to use a graph, slope means ratio of vertical change to horizontal change.


(i)
{{{y=-(2/3)*6+3}}}
{{{y=-2+3}}}
{{{y=1}}}


(ii)
{{{y=-(2/3)9+3}}}
{{{y=-6+9}}}
{{{y=3}}}