Question 1106389
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The average of the four integers is 222/4 = 55.5.<br>
The four consecutive integers whose sum is 222 are the two integers on each side of 55.5 and closest to 55.5: 54, 55, 56, and 57.<br>
Algebraically....
Let the four numbers be x, x+1, x+2, and x+3.  Then
{{{x+x+1+x+2+x+3 = 222}}}
{{{4x+6 = 222}}}
{{{4x = 216}}}
{{{x = 54}}}
The four numbers are 54, 55, 56, and 57.