Question 1106357
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Had all 10 points be in general position (such that no three of them are collinear), we would have {{{C[10]^2}}} = {{{(10*9)/(1*2)}}} = 45 different straight lines.

From this amount we need subtract {{{C[4]^2}}} = {{{(4*3)/(1*2)}}} = 6 lines connecting collinear points pairly, and replace them by only one single line.


So, the answer is 45 - 6 + 1 = 40 lines.


<U>Answer</U>.  There are 40 different straight lines connecting given 10 points.
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