Question 1106349
<br>
No base is specified, so it is assumed the base is 10.  Then<br>
1 = log_10(10)
2log_10(x) = log_10(x^2)<br>
Then
1+2logx
 = 1+2log_10(x)
 = log_10(10)+log_10(x^2)
 = log_10[(10)*(x^2)]
 = log_10(10x^2)
 = log(10x^2)<br>
Answer: 1+2logx = log(10x^2)