Question 1106341
log(4^(x+1)) = log(23)
OK, remember that the logarithm of a number raised to a power is the power times the logarithm of the number:
(x+1)log(4) = log(23)
x+1 = (log(23))/(log(4))
now, log(a)/log(b) = log_b(a)
x+1 = log_4(23)
x = log_4(23)-1
x = log_2(23)/2 - 1
Note: to calculate log_2 in your calculator do the following:
log(23)/log(2) = 1.367278/0.30103 = 4.542
Now finish solving:
x = (4.542/2) -1  = 2.271-1 = 1.271