Question 1106320
-4x^2 + 9y^2 + 32x + 36y - 64 = 0 ; 
put positive square first and move constant to right side.  Group x and y
9y^2+36y-4x^2+32x=64.  Factor
9(y^2+4y)-4(x^2-8x)=64. Complete the square and add constants to right side
9(y^2+4y+4)-4(x^2-8x+16)=64+36-64
9(y+2)^2-4(x-4)^2=36.  Divide both sides by 36
(y-(-2))^2/4-(x-4)^2/9=1, write in the form of (y-k)^2/b^2-(x-h)^2/a^2=1, equation of hyperbola.