Question 1106285
{{{P[C]=P[D]=2*P[E]}}}
and
{{{P[C]+P[D]+P[E]=1}}}
Substituting,
{{{P[C]+P[C]+P[C]/2=1}}}
{{{(5/2)P[C]=1}}}
.
.
.
{{{P[C]=2/5}}}
{{{P[D]=2/5}}}
{{{P[E]=1/5}}}