Question 99093
x^2 - 6x -3 =0
we have to take 3 to the other side by adding 3 to both sides
x^2 - 6x -3 + 3= 0 +3
x^2 - 6x = 3
Now we have to complete the square by dividing 2 into 6 and then squaring it.
(6/2)^2 = (3)^2 = 9
Now we add 9 to both sides

x^2 - 6x + 9 = 3 + 9

(x-3)^2 = 12

Now we take the square root on both sides of the equation.

{{{sqrt((x-3)^2)= sqrt(12)}}}

x - 3 = 2{{{sqrt(3)}}}
x - 3 + 3 = 3 + 2{{{sqrt(3)}}}
x = 3 + 2{{{sqrt(3)}}} or x = 3 - 2{{{sqrt(3)}}}

Normally you would use the sqaure root sign and the plus or minus sign.
Hope this helps you...Good Luck...:)