Question 1105906
tan theta = 19/35 = 0.5429 and theta = tan^(-1) 0.5429 = 28.4975 approximately 28.5 degrees
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tan theta = 19/x
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x = 19/tan theta
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take the first derivative
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dx/dt = (-19/sin^2 theta) * d(theta)/dt
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we know d(theta)/dt = -0.25 degrees/minute and dx/dt is how fast the tip of the shadow is moving
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dx/dt = (-19/0.2277) * (-0.25) = 20.86 m/minute
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