Question 1106199
Assuming the ground is horizontal, and the wall surface is vertical,
you have a right triangle with the ladder as its hypotenuse.
According to the Pythagorean theorem,
if the ladder is exactly 6 ft from the bottom of the wall,
the top of the ladder will be {{{h}}} feet above the ground, with
{{{h^2+6^2=25^2}}}
{{{h^2+36=625}}}
{{{h^2=625-36}}}
{{{h^2=589}}}
{{{h=sqrt(589)=approximately24.26}}}
So the ladder could reach about 24 ft 3 inches.
For practical purposes, I would say 24 feet.
 
If the ladder top touches the wall {{{highlight(24.26)}}} feet above the ground,
with the bottom of the ladder 6 ft from the wall,
the slope  of the ladder is
{{{24.26/6=about}}}{{{highlight(4.04)}}} .
 
That slope is the tangent (opposite side divided by adjacent side)
of the angle will the ladder makes with the ground.
So, the calculator will tell you that an acute angle with a tangent of {{{4.04}}} measures about
{{{highlight(76.1^o)}}} .
 
All of the answers are numbers that cannot be expressed as exact decimals,
so approximate answers is all you can get.
Those are good enough for real life,
and hopefully accepted by any teacher.