<PRE><B>Question 1105923</B>
P(2)=e^(-3.2)*(3.2)^2/2! from the Poisson formula, 
 P(x)= e^(-lambda)*lambda^x/x!
=0.2087
=========================
For 6, e^(-3.2)*3.2^6/6!=0.0608
For 7, it is 0.0278
For 8, it is 0.0111
For 9, it is 0.0040
For 10, it is 0.0013
For 11, it is 0.0004
For 12, it is 0.0001
0.1055 is the probability.
It would have been a little faster to do 5, 4,3,1,and 0 and have subtracted that sum from 1.
=========================
0 is e^-3.2 or 0.0408
1 is 0.1304
2 is 0.2087 from above
Two or fewer emails would have probability of 0.3799.</PRE>