Question 1106038
(2 - x + 2x^2 - x^3)/(x - 2) 
 I keep getting - x^2 (x -2) 
 but the book states: 
 -(x^2 + 1) 
 My procedure is: 
 (2 - x + 2x^2 - x^3)/(x - 2) -->
 (-x^3 + 2x^2 -x +2)/(x -2)
= {{{((-x^3-x) + (2x^2+2))/(x-2)}}}
= {{{(-x(x^2+1) + 2(x^2+1))/(x-2)}}}
= {{{(-x+2)*(x^2+1))/(x-2)}}}
= {{{-(x^2+1)}}}
===========================
 - (x^3 - 2x^2 + x - 2)/(x -2) -->

 - (x^3 - 2x^2) (x - 2) - grouping -->
 - x^2 (x - 2) (x - 2)/(x - 2)
 cancel the (x - 2) and I get:
 - x^2 (x - 2) 
 Does anyone know where I made my error?