Question 1105966
a)  given all three rolls are even and there are three possibilities
6XX = (1/3) * (2/3) * (2/3) = 4/27
X6X = (2/3) * (1/3) * (2/3) = 4/27
XX6 = (2/3) * (2/3) * (1/3) = 4/27
Probability (P) (One of the rolls is a 6, given all rolls are even) = 3(4/27) = 12/27
:
can you now do the others?