Question 99072
{{{x=y^2-2y+1}}} Start with the given equation



{{{x=(y-1)(y-1)}}} Factor the right side (note: if you need help with factoring, check out this <a href=http://www.algebra.com/algebra/homework/playground/change-this-name4450.solver>solver</a>)



{{{x=(y-1)^2}}} Rewrite {{{(y-1)(y-1)}}} as {{{(y-1)^2}}}



{{{0+-sqrt(x)=y-1}}} Take the square root of both sides



{{{1+-sqrt(x)=y}}} Add 1 to both sides



So our equation breaks into two parts



{{{y=sqrt(x)+1}}} or {{{y=-sqrt(x)+1}}}



So the first part {{{y=sqrt(x)+1}}} looks like this



{{{ graph( 500, 500, -10, 10, -10, 10, sqrt(x)+1) }}}



and the second part {{{y=-sqrt(x)+1}}}  looks like this




{{{ graph( 500, 500, -10, 10, -10, 10, -sqrt(x)+1) }}}



Putting them together we get






{{{ graph( 500, 500, -10, 10, -10, 10, sqrt(x)+1, -sqrt(x)+1) }}} graph of {{{y=1+-sqrt(x)}}}