Question 1105957
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The width of the rectangle is 4/5 of its {{{cross(dimension)}}} LENGTH. Find the dimension of the rectangle if the perimeter become 62cm when each dimension is increased by 2cm.
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{{{system(w=(4/5)L,2(w+2)+2(L+2)=62)}}}


{{{2w+4+2L+4=62}}}
{{{2w+2L=54}}}
{{{4w+4L=108}}}
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{{{5w=4L}}}
{{{108-4w=5w}}}
{{{108=9w}}}
{{{highlight(w=12)}}}---------width, original rectangle
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{{{L=(5/4)*12}}}
{{{highlight(L=15)}}}----------length, original rectangle