Question 1105958
Three completely separate exercises:


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Find two consecutive even integers such that four times the first is three times the second. 
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The sum of three numbers is 171. The second number is 1/2 of the first and the third number is 3/4 of the first. Find the numbers. 
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Twice a number is added to the number, giving 90, Find the number. 
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You can decide which ONE of them is being done here.
{{{n+n/2+(3/4)n=171}}}

{{{8n+4n+6n=171*8}}}

{{{18n=171*8}}}

{{{n=(171*8)/18}}}

{{{n=76}}}

<pre>First, second, third numbers respectivly: 76, 38, 57</pre>