Question 1105949
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A particle is moving according to an equation of motion. Its position after t seconds is given by s(t) = 2t^3 - 11t^2 + 13t - 1. 
After 1 second its position is at 3. 
Where is the original position of the particle? Explain. How far from the starting point is the particle at the end of 5 seconds?
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0.  The info  "After 1 second its position is at 3." is EXCESSIVE, UNNECESSARY and is not used in the solution.

    It is overlayed by <U>this statement</U>: 

        "A particle is moving according to an equation of motion. 
         Its position after t seconds is given by s(t) = 2t^3 - 11t^2 + 13t - 1."



1.  "Where is the original position of the particle?"

    <U>Answer</U>:  Substitute t= 0 into the formula and calculate s(0).



2.  "How far from the starting point is the particle at the end of 5 seconds?".

    <U>Answer</U>:  Substitute t= 5 into the formula and calculate s(5).

             Then calculate  delta_s = s(5) - s(0).


             It will be your final answer.
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