Question 1105910
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A man invested a total of $1200 into two accounts, one paying a 4% dividend, the  other paying a 6% dividend.  
The total interest earned was $57.  How much was  invested into each account? 
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<pre>
    x +     y = 1200,    (1)   ("A man invested a total of $1200 into two accounts")
0.04x + 0.06y =   57.    (2)   ("The total interest earned was $57")


Thus you have the system of 2 equations in 2 unknowns.


You can solve it using the substitution method.
For it, express y = 1200-x from the first equation and substitute it into the second equation. You will get

0.04x + 0.06*(1200-x) = 57,

0.04x + 72 - 0.06x = 57  ====>  -0.02x = 57 - 72 = -15  ====>  x = {{{(-15)/(-0.02)}}} = 750.


So, $750 was invested at 4% and the rest  $1200 - $750 = $450 was invested at 6%.


<U>Check</U>.  0.04*750 + 0.06*450 = 57 dollars.   ! Correct !


<U>Answer</U>.  $750 was invested at 4% and $450 was invested at 6%.
</pre>


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To see other similar solved problems on investment, look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.



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