Question 1105794
Both diagonals of the rectangle have the same length as the diameter of the circle
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let l be the length of the rectangle and w be the width, then using the Pythagorean Theorem 
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l^2 + w^2 = 6.5^2 = 42.25
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l = sqrt(42.25 - w^2)
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we know the area(A) of the rectangle is 15 square inches and A = l * W, then
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sqrt(42.25 - w^2) * w = 15
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square both sides of =
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(42.25 - w^2) * w^2 = 15
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42.25w^2 - w^4 = 225
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w^4 -42.25w^2 +225 = 0
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let u = w^2, then
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u^2 -42.25u + 225 = 0
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(u-36) * (u-6.25) = 0
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u = 36 or u = 6.25
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since u = w^2, then w = sqrt(u)
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w = 6 or 2.5
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we have two possible rectangles
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l = 15/6 = 2.5, w = 6
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l = 15/2.5 = 6, w = 2.5
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