Question 1105781
Integers n and n+1;


{{{n+n^2=16(n+1)}}}

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{{{n+n^2=16n+16}}}

{{{n^2=15n+16}}}

{{{n^2-15n-16=0}}}

{{{(n-16)(n+1)=0}}}

The POSITIVE integer is  n=16.


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CHECK
Does that work?
{{{16+16^2=16(17)}}}
{{{272=272}}}
yes