Question 1105757
The perimeter of a rectangle is 800m and the are is 80m square .find the length of the rectangle
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2L + 2W = 800
L + w = 400 --> L = 400 - W
L*W = 80
Sub for L
W*(400-W) = 80
w^2 - 400W + 80 = 0
*[invoke solve_quadratic_equation 1,-400,80]
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W is one of the solutions, L is the other.