Question 1105693
CONSTANT RATES SITUATION
RT=Q for constant rate R, time quantity T, amount of something done Q.


<pre>
                   SPEED           TIME           CALORIES
WALKING             180                           
BICYCLE             260
TOTALS                              8              1800
</pre>


Hope to burn 1800?
Can do Total of 8 hours?
Use w for number of hours spent walking:


<pre>
                   SPEED           TIME           CALORIES
WALKING             180             w               180w                        
BICYCLE             260            8-w           260(8-w)
TOTALS                              8              1800
</pre>


You can form the inequality  {{{highlight_green(180w+260(8-w)<=1800)}}}.
Simplify and solve this for w...