Question 1105520
{{{(4/5a^2b)*(-1/8bc^2)*(-10a)}}}
= {{{(4/5a^2b)*(1/8bc^2)*(10a)}}}
= {{{(40/5ab)*(1/8bc^2)}}}
= {{{(8/ab)*(1/8bc^2)}}}
= {{{(1/ab)*(1/bc^2)}}}
= {{{(1/ab^2c^2)}}}
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{{{2x*(-x^2y)*(-x^2)}}}
= {{{2x*(x^2y)*x^2}}}
= {{{2x^5y}}}