Question 1105621
Find the exact area enclosed between the curve y = sqrt(4 - x^2) and the line x+2=y. 
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The INT of sqrt(4 - x^2) is not correct.
{{{INT(sqrt(4-x^2)) = (x*sqrt(4-x^2) + 4arcsin(x/2))/2}}}
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The area is pi-2.  It's negative because is left of the y-axis, so it's the abs(2-pi).