Question 1105533
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With the information given in this way, I can't tell whether substitution or elimination would be easier.  Since the other tutor showed a solution using substitution, let me try elimination.<br>
That means using two variables:
let x = number of dimes
then 3x = number of quarters
let y = number of nickels<br>
{{{x+3x+y = 27}}}  the total number of coins is 27
(1) {{{4x+y = 27}}}
{{{10(x)+25(3x)+5(y) = 330}}}  the total value of the coins (in cents) is 330
{{{85x+5y = 330}}}
(2){{{17x+y = 66}}}<br>
Subtracting (1) from (2):
{{{13x = 39}}}
{{{x = 3}}}<br>
So the number of dimes is x=3; the number of quarters is 3x=9; and since the total number of coins is 27, the number of nickels is 15.<br>
HMMM.... Looks very different than the solution using substitution... and both methods seem to require about the same a mount of work....