Question 1105537
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1-st person can go out at any of 10 bus stops - 10 opportunities.
2-nd person can go out at any of 10 bus stops - 10 independent opportunities.
3-rd person can go out at any of 10 bus stops - 10 independent opportunities.
4-th person can go out at any of 10 bus stops - 10 independent opportunities.
5-th person can go out at any of 10 bus stops - 10 independent opportunities.
6-th person can go out at any of 10 bus stops - 10 independent opportunities.


In all, there are  {{{10^6}}} different ways.


Same number of ways as how many 6-letter words do exist comprising of 10 given letters (symbols) of the alphabet, if letters repetition is allowed.
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