Question 1105531
3x^2+x-4/(x-1)
discontinuity at x=1, for denominator is 0.
(3x+4)(x-1)/(x-1) is factored form of numerator.
Because x-1 cancels, it is a hole rather than an asymptote, and that hole is the discontinuity.
3x+4=0
x=-4/3 is the zero.
{{{graph(300,300,-10,10,-10,10,(3x^2+x-4)/(x-1))}}}