Question 1105251
x-4/ x-3 + 6/ x2-9


I believe you have {{{(x-4)/(x-3) + 6/(x^2-9)}}}.


Simplest common denominator would be  {{{(x-3)(x+3)=x^2-9}}}.


{{{((x-4)/(x-3))((x+3)/(x+3))+6/(x^2-9)}}}


{{{((x-4)(x+3)+6)/(x^2-9)}}}


{{{(x^2-x-12+6)/(x^2-9)}}}


{{{(x^2-x-6)/(x^2-9)}}} and this is probably the form you want; otherwise, if reducing is possible, the meaning may be changed.