Question 1105173
This is ambiguous:   <pre>square root of (3p^2 - 11) - x = 0 
If p > 0 and x = 8 in the equation above,...</pre>



Assuming you really have  {{{sqrt(3p^2-11)-8=0}}}, based on the way your parentheses appear, then you need  {{{3p^2-11>=0}}} but also  {{{sqrt(3p^2-11)=8}}}.  The equation is important.


Square both sides of that last form.
{{{3p^2-11=64}}}
{{{3p^2=64+11=75}}}
{{{p^2=75/3=25}}}

For the positive p,  {{{highlight(p=5)}}}.