Question 1105182
If 64^2n+1 = 16^4n-1, what is the value of n?
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If you mean If 64^(2n+1) = 16^(4n-1), what is the value of n?
(4^3)^(2n+1) = (4^2)^(4n-1)
4^(6n+3) = 4^(8n-2)
6n+3 = 8n-2
n = 5/2