<PRE><B>Question 1105145</B>
&lt;br&gt;
Let n be the number of dimes; then the number of nickels is n+3.&lt;br&gt;
The total value of the n dimes (10 cents each) and (n+3) nickels (5 cents each) is $1.95, or 195 cents:&lt;br&gt;
{{{10(n)+5(n+3) = 195}}}&lt;br&gt;
Solve using basic algebra.&lt;br&gt;
You can also solve this using logical reasoning; the calculations are the same as those used in the formal algebraic solution.&lt;br&gt;
(1) Take away the &quot;extra&quot; 3 nickels (15 cents), leaving equal numbers of nickels and dimes, worth a total of 180 cents.
(2) Since 1 dime and 1 nickel makes 15 cents, the number of nickels and dimes is each 180/15 = 12.
(3) Now put back the 3 nickels you took away.&lt;br&gt;
You end up with the answer, which is 12 dimes and 15 nickels.</PRE>