Question 1105014
A=Aoe^kt
A/Ao=2=e^kt
ln 2=kt
t=18
therefore, k=ln2/18=0.0385
A=50*e^(0.0385*60)=503.72 or 504.
Check
After 18 hours the population is 100.
After 36 hours, 200
After 54 hours 400
After 72 hours 800.
{{{graph(300,300,-50,80,-100,1000,50*e^(0.0385x))}}}