Question 1104987
let x = number of small vases.
let y = number of large vases.


there are 8 roses in a small vase.
there are 12 roses in a large vase.


your constraints and their associated equations are shown below:


there should be no more than 300 roses total.


8x + 12y <= 300


there need to be at least twice as many small vases as large vases.


x >= 2y


there are at least 6 small vases and no more than 12 large vases.


x >= 6
y <= 12


unspoken, but there:


the number of small vases and large vases must be greater than or equal to 0.


y >= 0


x >= 0 not required since x >= 6 takes care of that.


summary of constraint equations:


8x + 12y <= 300
x >= 2y
x >= 6
y <= 12
y >= 0


if you graph the opposite of these inequalities using the desmos.com calculator, the unshaded area of the graph will be your feasibility region.


that graph is shown below.


the maximum or minimum value of the objective function will be at the corner points of the feasible region.


since this problem doesn't have an objective function, the value at those corner points is not used.


<img src = "http://theo.x10hosting.com/2017/121701.jpg" alt = "$$$">