Question 1104951
{{{6(x^2+(p/6)x+2)}}}



Just the quadratic factor
{{{(x+1)(x+2)}}}
This takes care of the leading term and the constant term in the quadratic factor.


{{{x^2+3x+2=x^2+px/6+2}}}


This means that {{{3=p/6}}}
{{{highlight(p=18)}}}