Question 1104804
z = a + bi ---- a complex number.
sin(z) = 2
Solve for z.
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This is quite tedious.
Look at http://www.suitcaseofdreams.net/Sine_Complex.htm
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--> {{{z = pi/2 + k*pi +-i*ln(2 +- sqrt(3))}}} 
k = integer