Question 1104837
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P(first marble is red):
On the first draw, there are 9 marbles, of which 2 are red; so P(red) = 2/9.<br>
P(second marble is blue):
On the second draw, there are 8 marbles, of which 3 are blue; so P(blue) = 3/8.<br>
Since both of these have to happen, we multiply the probabilities of each event:
P(red then blue) = (2/9)*(3/8) = 6/72 = 1/12.