Question 98815
   

    LET :
      THE LENGTH OF THE RECTANGLE = L
      THE WIDTH OF THE RECTANGLE = W
      THE PERIMETR OF THE RECTANGLE = P = 28

   WE KNOW THAT P = L +L + W +W
                P = 2(L+W)
                28 =2(L+W)

                        SINCE L = 4W 
                 28 = 2( 4W+W)
                 28 = 2*5W
                 28 = 10W
                 28/10 = W
                  2.8 = W

             L = 4W 
             L= 4*2.8
             L = 11.2

   SO, THE DIMENSIONS OF THE RECTANGLE ARE 2.8 IN. AND 11.2 IN.

   CHECK :

       P = L+L+W+W = 2(L+W)
       P = 2(11.2+2.8)
       P = 2*14
       P = 28