Question 1104682
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(1) Expand the expression on the left in the given equation.<br>
{{{(sinx+cosx)^2 = sinx^2+2sinx*cosx+cosx^2 = 1+2sinx*cosx = 1+sin2x}}}<br>
Then
{{{1+sin2x = 3/4}}}
{{{sin2x = -1/4}}}<br>
Then find (cos(2x))^2 using {{{(sin(2x))^2+cos(2x)^2 = 1}}}