<PRE><B>Question 1104654</B>
Given log3 a = c and log3 b=2c, then solve for a
SOLUTION
take the base for common logarithms as 10
rewrite each in index notation i.e
10^c = 3a, and 10^(2c)= 3b

let y= 10^c such that y=3a and y^2= 3b

this implies that (3a)^2=3b

therefore a^2=3b/9

a=(b/3)^0.5

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