Question 1104448
.
<pre>
6|x-2| - 15 = -9*|x-2| + 15  ====>

6|x-2| + 9|x-2| = 15 + 15  ====>

15|x-2| = 30  ====>

|x-2| = 2.  


The solutions are those "x" that are remoted at the distance of 2 units from the value of 2.


These solutions are  x= 0  and  x= 4.
</pre>