Question 1104342
{{{f(x)=x^2-4x+5}}}


Add and subtract  {{{(4/2)^2}}} to the right hand side and put into the form in which you can directly read the vertex AND the symmetry axis.


{{{y=x^2-4x+4-4+5}}}

{{{highlight(y=(x-2)^2+1)}}}

Vertex is  (2,1) and axis of symmetry is x=2.