Question 1104284
If 10% of the water initially in the tank is lost in one day,
the water lost in a day is {{{"10%"=10/100=1/10=0.1}}}
of the water in the tank at the beginning of that day
(or at the end of the day before).
The next day the tank will hold a fraction of the water it had at the end of the day before.
What fraction?
{{{"100%"-"10%"="90%"=90/100=9/10=0.9}}}
So, by the end of the first day, the volume of water, in litres, in the tank will be
{{{6000*0.9}}} .
By the end of the second day, it will be {{{6000*0.9*0.9=6000*0.9^2}}} .
It will be {{{6000*0.9^3}}} by the end of the third day, and so on.
By the end of the fourth day, the volume of water, in litres, in the tank will be
{{{6000*0.9^4=6000*0.6561=3936.6}}} .
Then, the volume of water, in litres, that will leak during the fifth day is 10% of that, or
{{{3936.6*0.1=highlight(393.66)}}} .
By the end of the fifth day, the tank will hold
{{{3936.6L-393.66L=3542.94L}}} .
If the tank contained {{{"6000.00 L"}}} of water at the beginning,
over the course of the five days it would have lost
{{{"6000.00 L"-3542.94L=highlight(2457.06L)}}} of water.