Question 1104241
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Probably the easiest place to start is with {{{ac^3=135}}}. The prime factorization of 135 is {{{135 = 3*3*3*5}}}; that means a=5 an c=3.<br>
Then {{{a^3b = 5^3*b = 125b = 1375}}} so b is 11.<br>
Then a+b+c = 5+11+3 = 19.