Question 1104159
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I suppose you are supposed to solve this using algebra....<br>
But let's first think about solving it using logical reasoning.<br>
"Two games cost as much as five songs"; "the cost of two games and three songs is $16."<br>
Since the two games that were bought cost the same as five songs, the same $16 would have bought five songs plus three more songs, or eight songs.<br>
8 songs for $16 means each song costs $2.<br>
Then five songs would cost $10; and since that is the same cost as two games, each game costs 10/2 = $5.<br>
So the cost of one song and one game would be $2+$5 = $7.<br>
Now for the formal algebra...
(1) {{{2g = 5s}}}  [2 games cost the same as 5 songs]
(2) {{{2g+3s=16}}}  [2 games and 3 songs cost $16]
(3) {{{5s+3s=16}}}  [substitute (1) into (2)]
(4) {{{8s=16}}}; {{{s=2}}}  [solve (3) for the cost of each song]
(5) {{{2g = 5(2) = 10}}}; {{{g=5}}}  [substitute (4) in (1) and solve to find the cost of each game]
(6) {{{s+g = 2+5 = 7}}}  [answer the question: what is the cost of one song and one game]<br>
If you follow the steps, you will see the algebraic solution uses EXACTLY the same steps as the solution using logical reasoning....