Question 1104152
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(1) The traditional algebraic solution....<br>
Use x ounces of A and (60-x) ounces of B.
The amount of salt in x ounces of A is .70(x); the amount in (60-x) ounces of B is .95(60-x); the amount of salt in the mixture is .80(60).<br>
Write and solve the equation that says the amount of salt in the two ingredients is equal to the amount in the mixture:<br>
{{{.70(x)+.95(60-x) = .80(60)}}}<br>
I'll let you finish from there....<br>
(2) But here is an easier way to answer this kind of "mixture" problem:<br>
Look at the percentages of the two ingredients and of the mixture, as if on a number line.
80 is 2/5 of the way from 70 to 95.  (80-70=10; 95-70=25; 10/25 = 2/5).
That 2/5 means 2/5 of the mixture must be the 95% ingredient, B.<br>
2/5 of 60 is 24; so use 24 ounces of B and 36 ounces of A.<br>
If you finished the solution above using the standard algebraic method, that is the answer you should have gotten.