Question 1104013
Cosine is adjacent over hypotenuse so ADJ=5, HYP=7.
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*[illustration HYP2.png].
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Solving for Y.
{{{5^2+Y^2=7^2}}}
{{{Y^2=49-25}}}
{{{Y^2=24}}}
{{{Y=sqrt(24)}}}
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{{{sin(A)=Y/7}}}
{{{tan(A)=Y/5}}}
{{{csc(A)=1/sin(A)=7/Y}}}
{{{sec(A)=1/cos(A)=5/7}}}
{{{cot(A)=1/tan(A)=5/Y}}}
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Oops I used {{{A}}} instead of {{{theta}}}